Base | Representation |
---|---|
bin | 101100010001000101… |
… | …001011011001100101 |
3 | 11112200112100122212211 |
4 | 230101011023121211 |
5 | 1234320442212331 |
6 | 33500250443421 |
7 | 3301603423156 |
oct | 542105133145 |
9 | 145615318784 |
10 | 47531210341 |
11 | 1918114691a |
12 | 9266133571 |
13 | 463644a444 |
14 | 242c8c592d |
15 | 1382c818b1 |
hex | b1114b665 |
47531210341 has 2 divisors, whose sum is σ = 47531210342. Its totient is φ = 47531210340.
The previous prime is 47531210339. The next prime is 47531210393. The reversal of 47531210341 is 14301213574.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 34473348900 + 13057861441 = 185670^2 + 114271^2 .
It is a cyclic number.
It is not a de Polignac number, because 47531210341 - 21 = 47531210339 is a prime.
Together with 47531210339, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (47531210941) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 23765605170 + 23765605171.
It is an arithmetic number, because the mean of its divisors is an integer number (23765605171).
Almost surely, 247531210341 is an apocalyptic number.
It is an amenable number.
47531210341 is a deficient number, since it is larger than the sum of its proper divisors (1).
47531210341 is an equidigital number, since it uses as much as digits as its factorization.
47531210341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10080, while the sum is 31.
The spelling of 47531210341 in words is "forty-seven billion, five hundred thirty-one million, two hundred ten thousand, three hundred forty-one".
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