Search a number
-
+
476433113341 is a prime number
BaseRepresentation
bin1101110111011011010…
…00000110000011111101
31200112202102221211100111
412323231220012003331
530301213334111331
61002511555030021
746264312434103
oct6735550060375
91615672854314
10476433113341
11174066087769
127840459b311
1335c097b8123
14190b932bc73
15c5d6b96db1
hex6eeda060fd

476433113341 has 2 divisors, whose sum is σ = 476433113342. Its totient is φ = 476433113340.

The previous prime is 476433113329. The next prime is 476433113353. The reversal of 476433113341 is 143311334674.

It is a balanced prime because it is at equal distance from previous prime (476433113329) and next prime (476433113353).

It can be written as a sum of positive squares in only one way, i.e., 464549933241 + 11883180100 = 681579^2 + 109010^2 .

It is a cyclic number.

It is not a de Polignac number, because 476433113341 - 27 = 476433113213 is a prime.

It is a super-2 number, since 2×4764331133412 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 476433113294 and 476433113303.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (476433113381) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 238216556670 + 238216556671.

It is an arithmetic number, because the mean of its divisors is an integer number (238216556671).

Almost surely, 2476433113341 is an apocalyptic number.

It is an amenable number.

476433113341 is a deficient number, since it is larger than the sum of its proper divisors (1).

476433113341 is an equidigital number, since it uses as much as digits as its factorization.

476433113341 is an evil number, because the sum of its binary digits is even.

The product of its digits is 217728, while the sum is 40.

The spelling of 476433113341 in words is "four hundred seventy-six billion, four hundred thirty-three million, one hundred thirteen thousand, three hundred forty-one".