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47953547353 is a prime number
BaseRepresentation
bin101100101010010000…
…010001000001011001
311120202222001121100101
4230222100101001121
51241202102003403
634010214535401
73315222266335
oct545220210131
9146688047311
1047953547353
1119378588978
129363667561
1346a2aacaba
14246ca227c5
1513a9da871d
hexb2a411059

47953547353 has 2 divisors, whose sum is σ = 47953547354. Its totient is φ = 47953547352.

The previous prime is 47953547321. The next prime is 47953547359. The reversal of 47953547353 is 35374535974.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 45758343744 + 2195203609 = 213912^2 + 46853^2 .

It is a cyclic number.

It is not a de Polignac number, because 47953547353 - 25 = 47953547321 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 47953547294 and 47953547303.

It is not a weakly prime, because it can be changed into another prime (47953547359) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 23976773676 + 23976773677.

It is an arithmetic number, because the mean of its divisors is an integer number (23976773677).

Almost surely, 247953547353 is an apocalyptic number.

It is an amenable number.

47953547353 is a deficient number, since it is larger than the sum of its proper divisors (1).

47953547353 is an equidigital number, since it uses as much as digits as its factorization.

47953547353 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 23814000, while the sum is 55.

The spelling of 47953547353 in words is "forty-seven billion, nine hundred fifty-three million, five hundred forty-seven thousand, three hundred fifty-three".