Base | Representation |
---|---|
bin | 1101111111111000001… |
… | …01101101101011101111 |
3 | 1200222110200021102220022 |
4 | 12333330011231223233 |
5 | 30340012001214002 |
6 | 1004542131512355 |
7 | 46514621500643 |
oct | 6777405555357 |
9 | 1628420242808 |
10 | 480970726127 |
11 | 175a84488381 |
12 | 792701586bb |
13 | 364809009c8 |
14 | 193c9c28c23 |
15 | c7a0214ba2 |
hex | 6ffc16daef |
480970726127 has 2 divisors, whose sum is σ = 480970726128. Its totient is φ = 480970726126.
The previous prime is 480970726043. The next prime is 480970726129. The reversal of 480970726127 is 721627079084.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 480970726127 - 214 = 480970709743 is a prime.
It is a super-3 number, since 3×4809707261273 (a number of 36 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
Together with 480970726129, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (480970726129) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 240485363063 + 240485363064.
It is an arithmetic number, because the mean of its divisors is an integer number (240485363064).
Almost surely, 2480970726127 is an apocalyptic number.
480970726127 is a deficient number, since it is larger than the sum of its proper divisors (1).
480970726127 is an equidigital number, since it uses as much as digits as its factorization.
480970726127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2370816, while the sum is 53.
The spelling of 480970726127 in words is "four hundred eighty billion, nine hundred seventy million, seven hundred twenty-six thousand, one hundred twenty-seven".
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