Search a number
-
+
48195343391 = 133707334107
BaseRepresentation
bin101100111000101010…
…101001010000011111
311121101211001010011012
4230320222221100133
51242201001442031
634050213245435
73324216442136
oct547052512037
9147354033135
1048195343391
1119492018908
12941063387b
134710c0c290
142492ba491d
1513c121bb2b
hexb38aa941f

48195343391 has 4 divisors (see below), whose sum is σ = 51902677512. Its totient is φ = 44488009272.

The previous prime is 48195343381. The next prime is 48195343403. The reversal of 48195343391 is 19334359184.

48195343391 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-48195343391 is a prime.

It is a super-2 number, since 2×481953433912 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (48195343331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1853667041 + ... + 1853667066.

It is an arithmetic number, because the mean of its divisors is an integer number (12975669378).

Almost surely, 248195343391 is an apocalyptic number.

48195343391 is a deficient number, since it is larger than the sum of its proper divisors (3707334121).

48195343391 is a wasteful number, since it uses less digits than its factorization.

48195343391 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3707334120.

The product of its digits is 1399680, while the sum is 50.

The spelling of 48195343391 in words is "forty-eight billion, one hundred ninety-five million, three hundred forty-three thousand, three hundred ninety-one".

Divisors: 1 13 3707334107 48195343391