Base | Representation |
---|---|
bin | 101100111111100011… |
… | …110000100011100101 |
3 | 11121200212122000002201 |
4 | 230333203300203211 |
5 | 1242420102310124 |
6 | 34105503534501 |
7 | 3330122354443 |
oct | 547743604345 |
9 | 147625560081 |
10 | 48310978789 |
11 | 19541319457 |
12 | 94432ba431 |
13 | 472bb686a8 |
14 | 24a42a5b93 |
15 | 13cb45e144 |
hex | b3f8f08e5 |
48310978789 has 2 divisors, whose sum is σ = 48310978790. Its totient is φ = 48310978788.
The previous prime is 48310978763. The next prime is 48310978819. The reversal of 48310978789 is 98787901384.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 39168368100 + 9142610689 = 197910^2 + 95617^2 .
It is a cyclic number.
It is not a de Polignac number, because 48310978789 - 219 = 48310454501 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 48310978789.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (48310978489) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24155489394 + 24155489395.
It is an arithmetic number, because the mean of its divisors is an integer number (24155489395).
Almost surely, 248310978789 is an apocalyptic number.
It is an amenable number.
48310978789 is a deficient number, since it is larger than the sum of its proper divisors (1).
48310978789 is an equidigital number, since it uses as much as digits as its factorization.
48310978789 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24385536, while the sum is 64.
The spelling of 48310978789 in words is "forty-eight billion, three hundred ten million, nine hundred seventy-eight thousand, seven hundred eighty-nine".
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