Base | Representation |
---|---|
bin | 110111000010011000110000… |
… | …0001110101111001000011111 |
3 | 2100111002202122200010112200221 |
4 | 1232010301200032233020133 |
5 | 1001423202211420233433 |
6 | 4433342302100302211 |
7 | 203654010054023341 |
oct | 15604614016571037 |
9 | 2314082580115627 |
10 | 484113148211743 |
11 | 1302872623a85a6 |
12 | 463684559a1967 |
13 | 17a1889b9b0a7b |
14 | 87792b68a9291 |
15 | 3ae7d621d872d |
hex | 1b84c603af21f |
484113148211743 has 2 divisors, whose sum is σ = 484113148211744. Its totient is φ = 484113148211742.
The previous prime is 484113148211741. The next prime is 484113148211809. The reversal of 484113148211743 is 347112841311484.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 484113148211743 - 21 = 484113148211741 is a prime.
Together with 484113148211741, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (484113148211741) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 242056574105871 + 242056574105872.
It is an arithmetic number, because the mean of its divisors is an integer number (242056574105872).
Almost surely, 2484113148211743 is an apocalyptic number.
484113148211743 is a deficient number, since it is larger than the sum of its proper divisors (1).
484113148211743 is an equidigital number, since it uses as much as digits as its factorization.
484113148211743 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2064384, while the sum is 52.
The spelling of 484113148211743 in words is "four hundred eighty-four trillion, one hundred thirteen billion, one hundred forty-eight million, two hundred eleven thousand, seven hundred forty-three".
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