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48412515614213 is a prime number
BaseRepresentation
bin10110000000111111010101…
…10010111011111000000101
320100102012011110012212020202
423000133222302323320011
522321142312444123323
6250544222545340245
713124455160656202
oct1300375262737005
9210365143185222
1048412515614213
11144756a5a52923
12551a805637685
13210238572292a
14bd526d1d6ca9
1558e4c21ead28
hex2c07eacbbe05

48412515614213 has 2 divisors, whose sum is σ = 48412515614214. Its totient is φ = 48412515614212.

The previous prime is 48412515614179. The next prime is 48412515614231. The reversal of 48412515614213 is 31241651521484.

It is a happy number.

Together with next prime (48412515614231) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 31939486159009 + 16473029455204 = 5651503^2 + 4058698^2 .

It is a cyclic number.

It is not a de Polignac number, because 48412515614213 - 242 = 44014469103109 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (48412515614233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24206257807106 + 24206257807107.

It is an arithmetic number, because the mean of its divisors is an integer number (24206257807107).

Almost surely, 248412515614213 is an apocalyptic number.

It is an amenable number.

48412515614213 is a deficient number, since it is larger than the sum of its proper divisors (1).

48412515614213 is an equidigital number, since it uses as much as digits as its factorization.

48412515614213 is an evil number, because the sum of its binary digits is even.

The product of its digits is 921600, while the sum is 47.

The spelling of 48412515614213 in words is "forty-eight trillion, four hundred twelve billion, five hundred fifteen million, six hundred fourteen thousand, two hundred thirteen".