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487313125104 = 243133191072273
BaseRepresentation
bin1110001011101100010…
…00000010111011110000
31201120211200121200200010
413011312020002323300
530441004130000404
61011511335254520
750131034135031
oct7056610027360
91646750550603
10487313125104
11178739611623
127a54021a440
1336c518c1000
141982c2c6a88
15ca21e34189
hex7176202ef0

487313125104 has 320 divisors, whose sum is σ = 1449582220800. Its totient is φ = 140661301248.

The previous prime is 487313125097. The next prime is 487313125129. The reversal of 487313125104 is 401521313784.

It is a Harshad number since it is a multiple of its sum of digits (39).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 214390912 + ... + 214393184.

It is an arithmetic number, because the mean of its divisors is an integer number (4529944440).

Almost surely, 2487313125104 is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 487313125104, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (724791110400).

487313125104 is an abundant number, since it is smaller than the sum of its proper divisors (962269095696).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

487313125104 is a wasteful number, since it uses less digits than its factorization.

487313125104 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2449 (or 2417 counting only the distinct ones).

The product of its (nonzero) digits is 80640, while the sum is 39.

Adding to 487313125104 its reverse (401521313784), we get a palindrome (888834438888).

The spelling of 487313125104 in words is "four hundred eighty-seven billion, three hundred thirteen million, one hundred twenty-five thousand, one hundred four".