Base | Representation |
---|---|
bin | 10110001011011111110100… |
… | …01000010110101001100011 |
3 | 20101200201001120101001100002 |
4 | 23011233322020112221203 |
5 | 22343101212313440003 |
6 | 251422132024250215 |
7 | 13162526016545453 |
oct | 1305577210265143 |
9 | 211621046331302 |
10 | 48773550140003 |
11 | 145a4823591777 |
12 | 557878331096b |
13 | 212a431416850 |
14 | c0891c365d63 |
15 | 598aa2d5da88 |
hex | 2c5bfa216a63 |
48773550140003 has 16 divisors (see below), whose sum is σ = 55290522094080. Its totient is φ = 42651658331424.
The previous prime is 48773550139991. The next prime is 48773550140047. The reversal of 48773550140003 is 30004105537784.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 48773550140003 - 24 = 48773550139987 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 48773550140003.
It is not an unprimeable number, because it can be changed into a prime (48773550140053) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 20068700 + ... + 22367382.
It is an arithmetic number, because the mean of its divisors is an integer number (3455657630880).
Almost surely, 248773550140003 is an apocalyptic number.
48773550140003 is a deficient number, since it is larger than the sum of its proper divisors (6516971954077).
48773550140003 is a wasteful number, since it uses less digits than its factorization.
48773550140003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2384618.
The product of its (nonzero) digits is 1411200, while the sum is 47.
Adding to 48773550140003 its reverse (30004105537784), we get a palindrome (78777655677787).
The spelling of 48773550140003 in words is "forty-eight trillion, seven hundred seventy-three billion, five hundred fifty million, one hundred forty thousand, three".
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