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48980253893 is a prime number
BaseRepresentation
bin101101100111011100…
…110101110011000101
311200102111222200221112
4231213130311303011
51300302421111033
634300132454405
73352530201014
oct554734656305
9150374880845
1048980253893
111985509277a
1295ab47a405
13480770ab6c
142529122a7b
15141a0b2c48
hexb67735cc5

48980253893 has 2 divisors, whose sum is σ = 48980253894. Its totient is φ = 48980253892.

The previous prime is 48980253863. The next prime is 48980253923. The reversal of 48980253893 is 39835208984.

It is a balanced prime because it is at equal distance from previous prime (48980253863) and next prime (48980253923).

It can be written as a sum of positive squares in only one way, i.e., 48974575204 + 5678689 = 221302^2 + 2383^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-48980253893 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (48980253863) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24490126946 + 24490126947.

It is an arithmetic number, because the mean of its divisors is an integer number (24490126947).

Almost surely, 248980253893 is an apocalyptic number.

It is an amenable number.

48980253893 is a deficient number, since it is larger than the sum of its proper divisors (1).

48980253893 is an equidigital number, since it uses as much as digits as its factorization.

48980253893 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14929920, while the sum is 59.

The spelling of 48980253893 in words is "forty-eight billion, nine hundred eighty million, two hundred fifty-three thousand, eight hundred ninety-three".