490000001 has 2 divisors, whose sum is σ = 490000002. Its totient is φ = 490000000.

The previous prime is 489999997. The next prime is 490000003. The reversal of 490000001 is 100000094.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 486158401 + 3841600 = 22049^2 + 1960^2 .

It is a cyclic number.

It is not a de Polignac number, because 490000001 - 2² = 489999997 is a prime.

Together with 490000003, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (490000003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 245000000 + 245000001.

It is an arithmetic number, because the mean of its divisors is an integer number (245000001).

Almost surely, 2^490000001 is an apocalyptic number.

It is an amenable number.

490000001 is a deficient number, since it is larger than the sum of its proper divisors (1).

490000001 is an equidigital number, since it uses as much as digits as its factorization.

490000001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36, while the sum is 14.

The square root of 490000001 is about 22135.9436437664. The cubic root of 490000001 is about 788.3735168468.

Adding to 490000001 its reverse (100000094), we get a palindrome (590000095).

The spelling of 490000001 in words is "four hundred ninety million, one", and thus it is an aban number.