490000003 has 2 divisors, whose sum is σ = 490000004. Its totient is φ = 490000002.

The previous prime is 490000001. The next prime is 490000013. The reversal of 490000003 is 300000094.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 490000003 - 2¹ = 490000001 is a prime.

Together with 490000001, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (490000001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 245000001 + 245000002.

It is an arithmetic number, because the mean of its divisors is an integer number (245000002).

Almost surely, 2^490000003 is an apocalyptic number.

490000003 is a deficient number, since it is larger than the sum of its proper divisors (1).

490000003 is an equidigital number, since it uses as much as digits as its factorization.

490000003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108, while the sum is 16.

The square root of 490000003 is about 22135.9436889417. The cubic root of 490000003 is about 788.3735179194.

Adding to 490000003 its reverse (300000094), we get a palindrome (790000097).

The spelling of 490000003 in words is "four hundred ninety million, three", and thus it is an aban number.