Base | Representation |
---|---|
bin | 101101101000101000… |
… | …001010101001100101 |
3 | 11200110220010220122120 |
4 | 231220220022221211 |
5 | 1300323000000401 |
6 | 34302120020153 |
7 | 3353160062103 |
oct | 555050125145 |
9 | 150426126576 |
10 | 49000000101 |
11 | 1986524a358 |
12 | 95b6001659 |
13 | 480b832900 |
14 | 252b9c2c73 |
15 | 141bbb3836 |
hex | b68a0aa65 |
49000000101 has 48 divisors (see below), whose sum is σ = 74712347136. Its totient is φ = 28494742848.
The previous prime is 49000000079. The next prime is 49000000157. The reversal of 49000000101 is 10100000094.
It is not a de Polignac number, because 49000000101 - 25 = 49000000069 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (49000000001) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 942550 + ... + 993176.
It is an arithmetic number, because the mean of its divisors is an integer number (1556507232).
Almost surely, 249000000101 is an apocalyptic number.
It is an amenable number.
49000000101 is a deficient number, since it is larger than the sum of its proper divisors (25712347035).
49000000101 is a wasteful number, since it uses less digits than its factorization.
49000000101 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 50762 (or 50749 counting only the distinct ones).
The product of its (nonzero) digits is 36, while the sum is 15.
Adding to 49000000101 its reverse (10100000094), we get a palindrome (59100000195).
The spelling of 49000000101 in words is "forty-nine billion, one hundred one", and thus it is an aban number.
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