Search a number
-
+
49030138391 = 133771549107
BaseRepresentation
bin101101101010011011…
…001000101000010111
311200112222212002121112
4231222123020220113
51300403203412031
634305114005235
73354004204613
oct555233105027
9150488762545
1049030138391
1119880264733
12960411681b
134814b55810
1425319ca343
15141e66862b
hexb6a6c8a17

49030138391 has 4 divisors (see below), whose sum is σ = 52801687512. Its totient is φ = 45258589272.

The previous prime is 49030138387. The next prime is 49030138433. The reversal of 49030138391 is 19383103094.

49030138391 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 49030138391 - 22 = 49030138387 is a prime.

It is a super-2 number, since 2×490301383912 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (49030137391) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1885774541 + ... + 1885774566.

It is an arithmetic number, because the mean of its divisors is an integer number (13200421878).

Almost surely, 249030138391 is an apocalyptic number.

49030138391 is a deficient number, since it is larger than the sum of its proper divisors (3771549121).

49030138391 is a wasteful number, since it uses less digits than its factorization.

49030138391 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3771549120.

The product of its (nonzero) digits is 69984, while the sum is 41.

The spelling of 49030138391 in words is "forty-nine billion, thirty million, one hundred thirty-eight thousand, three hundred ninety-one".

Divisors: 1 13 3771549107 49030138391