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4908097408093 = 11446190673463
BaseRepresentation
bin100011101101100000101…
…1001110000110001011101
3122101012122202011201211221
41013123001121300301131
51120403240414024333
614234425425013341
71014412141422325
oct107330131606135
918335582151757
104908097408093
11162257003aa70
1267327ba84251
13297aa7041779
1412d7a5d08285
1587a0e323d2d
hex476c1670c5d

4908097408093 has 4 divisors (see below), whose sum is σ = 5354288081568. Its totient is φ = 4461906734620.

The previous prime is 4908097408073. The next prime is 4908097408169. The reversal of 4908097408093 is 3908047908094.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4908097408093 is a prime.

It is a super-3 number, since 3×49080974080933 (a number of 39 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4908097408033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 223095336721 + ... + 223095336742.

It is an arithmetic number, because the mean of its divisors is an integer number (1338572020392).

Almost surely, 24908097408093 is an apocalyptic number.

It is an amenable number.

4908097408093 is a deficient number, since it is larger than the sum of its proper divisors (446190673475).

4908097408093 is a wasteful number, since it uses less digits than its factorization.

4908097408093 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 446190673474.

The product of its (nonzero) digits is 15676416, while the sum is 61.

The spelling of 4908097408093 in words is "four trillion, nine hundred eight billion, ninety-seven million, four hundred eight thousand, ninety-three".

Divisors: 1 11 446190673463 4908097408093