Base | Representation |
---|---|
bin | 10110010101001100001000… |
… | …11101010000011000010111 |
3 | 20102212112200020010100212202 |
4 | 23022212010131100120113 |
5 | 22414030240314410301 |
6 | 252235130350035115 |
7 | 13225555625310101 |
oct | 1312460435203027 |
9 | 212775606110782 |
10 | 49106583356951 |
11 | 14712a9210a86a |
12 | 56112274a8a9b |
13 | 2152966b52073 |
14 | c1aab26c4571 |
15 | 5a259559c66b |
hex | 2ca984750617 |
49106583356951 has 2 divisors, whose sum is σ = 49106583356952. Its totient is φ = 49106583356950.
The previous prime is 49106583356933. The next prime is 49106583356977. The reversal of 49106583356951 is 15965338560194.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 49106583356951 - 222 = 49106579162647 is a prime.
It is a super-2 number, since 2×491065833569512 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (49106583352951) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24553291678475 + 24553291678476.
It is an arithmetic number, because the mean of its divisors is an integer number (24553291678476).
Almost surely, 249106583356951 is an apocalyptic number.
49106583356951 is a deficient number, since it is larger than the sum of its proper divisors (1).
49106583356951 is an equidigital number, since it uses as much as digits as its factorization.
49106583356951 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 104976000, while the sum is 65.
The spelling of 49106583356951 in words is "forty-nine trillion, one hundred six billion, five hundred eighty-three million, three hundred fifty-six thousand, nine hundred fifty-one".
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