Base | Representation |
---|---|
bin | 11101010001011… |
… | …100010000000111 |
3 | 1021020010001020021 |
4 | 131101130100013 |
5 | 2001211031211 |
6 | 120422120011 |
7 | 15112243516 |
oct | 3521342007 |
9 | 1236101207 |
10 | 491111431 |
11 | 232246318 |
12 | 118580007 |
13 | 7a9923a5 |
14 | 4932067d |
15 | 2d1ae771 |
hex | 1d45c407 |
491111431 has 2 divisors, whose sum is σ = 491111432. Its totient is φ = 491111430.
The previous prime is 491111377. The next prime is 491111437. The reversal of 491111431 is 134111194.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 491111431 - 225 = 457556999 is a prime.
It is a super-2 number, since 2×4911114312 = 482380875317735522, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 491111396 and 491111405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (491111437) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 245555715 + 245555716.
It is an arithmetic number, because the mean of its divisors is an integer number (245555716).
Almost surely, 2491111431 is an apocalyptic number.
491111431 is a deficient number, since it is larger than the sum of its proper divisors (1).
491111431 is an equidigital number, since it uses as much as digits as its factorization.
491111431 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 432, while the sum is 25.
The square root of 491111431 is about 22161.0340688335. The cubic root of 491111431 is about 788.9691361123.
The spelling of 491111431 in words is "four hundred ninety-one million, one hundred eleven thousand, four hundred thirty-one".
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