491121130303 has 4 divisors (see below), whose sum is σ = 491125190400. Its totient is φ = 491117070208.

The previous prime is 491121130259. The next prime is 491121130327. The reversal of 491121130303 is 303031121194.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 491121130303 - 2¹³ = 491121122111 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (491121130373) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1842850 + ... + 2092447.

It is an arithmetic number, because the mean of its divisors is an integer number (122781297600).

Almost surely, 2^491121130303 is an apocalyptic number.

491121130303 is a deficient number, since it is larger than the sum of its proper divisors (4060097).

491121130303 is a wasteful number, since it uses less digits than its factorization.

491121130303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4060096.

The product of its (nonzero) digits is 1944, while the sum is 28.

Adding to 491121130303 its reverse (303031121194), we get a palindrome (794152251497).

The spelling of 491121130303 in words is "four hundred ninety-one billion, one hundred twenty-one million, one hundred thirty thousand, three hundred three".