Base | Representation |
---|---|
bin | 1110010011001001011… |
… | …10000110010010010111 |
3 | 1201222011122212202100101 |
4 | 13021210232012102113 |
5 | 31022203403441334 |
6 | 1013412452354531 |
7 | 50332161516565 |
oct | 7114456062227 |
9 | 1658148782311 |
10 | 491316077719 |
11 | 17a403132125 |
12 | 7b278915a47 |
13 | 3743c00761c |
14 | 19acbba8a35 |
15 | cba858e214 |
hex | 7264b86497 |
491316077719 has 2 divisors, whose sum is σ = 491316077720. Its totient is φ = 491316077718.
The previous prime is 491316077657. The next prime is 491316077737. The reversal of 491316077719 is 917770613194.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 491316077719 - 27 = 491316077591 is a prime.
It is a super-2 number, since 2×4913160777192 (a number of 24 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 491316077719.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (491316077779) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 245658038859 + 245658038860.
It is an arithmetic number, because the mean of its divisors is an integer number (245658038860).
Almost surely, 2491316077719 is an apocalyptic number.
491316077719 is a deficient number, since it is larger than the sum of its proper divisors (1).
491316077719 is an equidigital number, since it uses as much as digits as its factorization.
491316077719 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2000376, while the sum is 55.
The spelling of 491316077719 in words is "four hundred ninety-one billion, three hundred sixteen million, seventy-seven thousand, seven hundred nineteen".
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