Base | Representation |
---|---|
bin | 101101110000100101… |
… | …001011000101101010 |
3 | 11200211012020000102222 |
4 | 231300211023011222 |
5 | 1301111124330234 |
6 | 34323243554042 |
7 | 3356400201626 |
oct | 556045130552 |
9 | 150735200388 |
10 | 49133433194 |
11 | 199235a663a |
12 | 963282b922 |
13 | 4830380bc1 |
14 | 25415d8186 |
15 | 142876e42e |
hex | b7094b16a |
49133433194 has 4 divisors (see below), whose sum is σ = 73700149794. Its totient is φ = 24566716596.
The previous prime is 49133433191. The next prime is 49133433197.
49133433194 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (49133433191) and next prime (49133433197).
It can be written as a sum of positive squares in only one way, i.e., 27740568025 + 21392865169 = 166555^2 + 146263^2 .
It is a super-2 number, since 2×491334331942 (a number of 22 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (49133433191) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12283358297 + ... + 12283358300.
Almost surely, 249133433194 is an apocalyptic number.
49133433194 is a deficient number, since it is larger than the sum of its proper divisors (24566716600).
49133433194 is a wasteful number, since it uses less digits than its factorization.
49133433194 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 24566716599.
The product of its digits is 419904, while the sum is 44.
The spelling of 49133433194 in words is "forty-nine billion, one hundred thirty-three million, four hundred thirty-three thousand, one hundred ninety-four".
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