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49133433194 = 224566716597
BaseRepresentation
bin101101110000100101…
…001011000101101010
311200211012020000102222
4231300211023011222
51301111124330234
634323243554042
73356400201626
oct556045130552
9150735200388
1049133433194
11199235a663a
12963282b922
134830380bc1
1425415d8186
15142876e42e
hexb7094b16a

49133433194 has 4 divisors (see below), whose sum is σ = 73700149794. Its totient is φ = 24566716596.

The previous prime is 49133433191. The next prime is 49133433197.

49133433194 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (49133433191) and next prime (49133433197).

It can be written as a sum of positive squares in only one way, i.e., 27740568025 + 21392865169 = 166555^2 + 146263^2 .

It is a super-2 number, since 2×491334331942 (a number of 22 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (49133433191) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12283358297 + ... + 12283358300.

Almost surely, 249133433194 is an apocalyptic number.

49133433194 is a deficient number, since it is larger than the sum of its proper divisors (24566716600).

49133433194 is a wasteful number, since it uses less digits than its factorization.

49133433194 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24566716599.

The product of its digits is 419904, while the sum is 44.

The spelling of 49133433194 in words is "forty-nine billion, one hundred thirty-three million, four hundred thirty-three thousand, one hundred ninety-four".

Divisors: 1 2 24566716597 49133433194