Base | Representation |
---|---|
bin | 100011110000010010110… |
… | …1000010110001011110111 |
3 | 122101210002021001000020221 |
4 | 1013200211220112023313 |
5 | 1121003010410421442 |
6 | 14241254442235211 |
7 | 1015013222064112 |
oct | 107404550261367 |
9 | 18353067030227 |
10 | 4914073920247 |
11 | 1625057689008 |
12 | 6744694b5b07 |
13 | 29851a2a56ab |
14 | 12dbb1961579 |
15 | 87c5dd6c467 |
hex | 47825a162f7 |
4914073920247 has 4 divisors (see below), whose sum is σ = 4914124635616. Its totient is φ = 4914023204880.
The previous prime is 4914073920199. The next prime is 4914073920299. The reversal of 4914073920247 is 7420293704194.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4914073920247 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 4914073920194 and 4914073920203.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4914073920347) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25212063 + ... + 25406224.
It is an arithmetic number, because the mean of its divisors is an integer number (1228531158904).
Almost surely, 24914073920247 is an apocalyptic number.
4914073920247 is a deficient number, since it is larger than the sum of its proper divisors (50715369).
4914073920247 is an equidigital number, since it uses as much as digits as its factorization.
4914073920247 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 50715368.
The product of its (nonzero) digits is 3048192, while the sum is 52.
The spelling of 4914073920247 in words is "four trillion, nine hundred fourteen billion, seventy-three million, nine hundred twenty thousand, two hundred forty-seven".
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