Base | Representation |
---|---|
bin | 100011110001101010010… |
… | …1111110100110000101101 |
3 | 122102001200000100111121110 |
4 | 1013203110233310300231 |
5 | 1121030020021041133 |
6 | 14242502153222233 |
7 | 1015146065331153 |
oct | 107432457646055 |
9 | 18361600314543 |
10 | 4917011893293 |
11 | 1626325033705 |
12 | 674b49401979 |
13 | 298897b80496 |
14 | 12ddadc1d3d3 |
15 | 87d81c5cc63 |
hex | 478d4bf4c2d |
4917011893293 has 16 divisors (see below), whose sum is σ = 6901553700800. Its totient is φ = 3105263226240.
The previous prime is 4917011893207. The next prime is 4917011893303. The reversal of 4917011893293 is 3923981107194.
It is a happy number.
It is not a de Polignac number, because 4917011893293 - 28 = 4917011893037 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (57).
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4917011893793) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2206198 + ... + 3834231.
It is an arithmetic number, because the mean of its divisors is an integer number (431347106300).
Almost surely, 24917011893293 is an apocalyptic number.
It is an amenable number.
4917011893293 is a deficient number, since it is larger than the sum of its proper divisors (1984541807507).
4917011893293 is a wasteful number, since it uses less digits than its factorization.
4917011893293 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6054732.
The product of its (nonzero) digits is 2939328, while the sum is 57.
The spelling of 4917011893293 in words is "four trillion, nine hundred seventeen billion, eleven million, eight hundred ninety-three thousand, two hundred ninety-three".
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