Base | Representation |
---|---|
bin | 100011110011001100010… |
… | …0011001111101110010011 |
3 | 122102101010221201200001212 |
4 | 1013212120203033232103 |
5 | 1121103232003231240 |
6 | 14244204143050335 |
7 | 1015323354563213 |
oct | 107463043175623 |
9 | 18371127650055 |
10 | 4920296930195 |
11 | 1627760388539 |
12 | 6757055a09ab |
13 | 298c9c623bba |
14 | 130202222243 |
15 | 87ec5357165 |
hex | 479988cfb93 |
4920296930195 has 8 divisors (see below), whose sum is σ = 5926305597840. Its totient is φ = 3921604689760.
The previous prime is 4920296930147. The next prime is 4920296930209. The reversal of 4920296930195 is 5910396920294.
4920296930195 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 4920296930195 - 240 = 3820785302419 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1829105321 + ... + 1829108010.
It is an arithmetic number, because the mean of its divisors is an integer number (740788199730).
Almost surely, 24920296930195 is an apocalyptic number.
4920296930195 is a deficient number, since it is larger than the sum of its proper divisors (1006008667645).
4920296930195 is a wasteful number, since it uses less digits than its factorization.
4920296930195 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3658213605.
The product of its (nonzero) digits is 9447840, while the sum is 59.
Subtracting 4920296930195 from its reverse (5910396920294), we obtain a palindrome (990099990099).
The spelling of 4920296930195 in words is "four trillion, nine hundred twenty billion, two hundred ninety-six million, nine hundred thirty thousand, one hundred ninety-five".
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