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49209502973 is a prime number
BaseRepresentation
bin101101110101000111…
…010110110011111101
311201000111100202120012
4231311013112303331
51301240113043343
634335002233005
73361312605461
oct556507266375
9151014322505
1049209502973
1119962532a24
1296541b5765
1348430663c7
14254b75a4a1
151430298718
hexb751d6cfd

49209502973 has 2 divisors, whose sum is σ = 49209502974. Its totient is φ = 49209502972.

The previous prime is 49209502949. The next prime is 49209502981. The reversal of 49209502973 is 37920590294.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 45242140804 + 3967362169 = 212702^2 + 62987^2 .

It is a cyclic number.

It is not a de Polignac number, because 49209502973 - 214 = 49209486589 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (49209502873) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24604751486 + 24604751487.

It is an arithmetic number, because the mean of its divisors is an integer number (24604751487).

Almost surely, 249209502973 is an apocalyptic number.

It is an amenable number.

49209502973 is a deficient number, since it is larger than the sum of its proper divisors (1).

49209502973 is an equidigital number, since it uses as much as digits as its factorization.

49209502973 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1224720, while the sum is 50.

The spelling of 49209502973 in words is "forty-nine billion, two hundred nine million, five hundred two thousand, nine hundred seventy-three".