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492110277149 is a prime number
BaseRepresentation
bin1110010100101000000…
…11101110101000011101
31202001020000022021011002
413022110003232220131
531030320212332044
61014023343040045
750360644224041
oct7122403565035
91661200267132
10492110277149
1117a780470997
127b45a8a0025
133753770920a
1419b65464021
15cc0316c74e
hex72940eea1d

492110277149 has 2 divisors, whose sum is σ = 492110277150. Its totient is φ = 492110277148.

The previous prime is 492110277133. The next prime is 492110277151. The reversal of 492110277149 is 941772011294.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 271321183225 + 220789093924 = 520885^2 + 469882^2 .

It is a cyclic number.

It is not a de Polignac number, because 492110277149 - 24 = 492110277133 is a prime.

Together with 492110277151, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (492110277649) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 246055138574 + 246055138575.

It is an arithmetic number, because the mean of its divisors is an integer number (246055138575).

Almost surely, 2492110277149 is an apocalyptic number.

It is an amenable number.

492110277149 is a deficient number, since it is larger than the sum of its proper divisors (1).

492110277149 is an equidigital number, since it uses as much as digits as its factorization.

492110277149 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 254016, while the sum is 47.

The spelling of 492110277149 in words is "four hundred ninety-two billion, one hundred ten million, two hundred seventy-seven thousand, one hundred forty-nine".