Base | Representation |
---|---|
bin | 100011110011100100100… |
… | …1000111010100010111111 |
3 | 122102110020202122011022110 |
4 | 1013213021020322202333 |
5 | 1121111414200030140 |
6 | 14244421103145103 |
7 | 1015352513525412 |
oct | 107471110724277 |
9 | 18373222564273 |
10 | 4921112111295 |
11 | 1628039548126 |
12 | 6758b25a5193 |
13 | 29909c490993 |
14 | 13027c5bdb79 |
15 | 88021bcc380 |
hex | 479c923a8bf |
4921112111295 has 32 divisors (see below), whose sum is σ = 8184013028352. Its totient is φ = 2522891187072.
The previous prime is 4921112111281. The next prime is 4921112111393. The reversal of 4921112111295 is 5921112111294.
It is not a de Polignac number, because 4921112111295 - 25 = 4921112111263 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 53368807 + ... + 53460936.
It is an arithmetic number, because the mean of its divisors is an integer number (255750407136).
Almost surely, 24921112111295 is an apocalyptic number.
4921112111295 is a deficient number, since it is larger than the sum of its proper divisors (3262900917057).
4921112111295 is a wasteful number, since it uses less digits than its factorization.
4921112111295 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 106829871.
The product of its digits is 12960, while the sum is 39.
Subtracting 4921112111295 from its reverse (5921112111294), we obtain a palindrome (999999999999).
The spelling of 4921112111295 in words is "four trillion, nine hundred twenty-one billion, one hundred twelve million, one hundred eleven thousand, two hundred ninety-five".
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