Base | Representation |
---|---|
bin | 10110011001010001000100… |
… | …11001000011111111111111 |
3 | 20110100221021020122100110222 |
4 | 23030220202121003333333 |
5 | 22423324141013330023 |
6 | 252423335300051555 |
7 | 13241645304235556 |
oct | 1314504231037777 |
9 | 213327236570428 |
10 | 49246672011263 |
11 | 1476743a546231 |
12 | 5634402993bbb |
13 | 2162c30bb461c |
14 | c237a19ccd9d |
15 | 5a6043e81cc8 |
hex | 2cca22643fff |
49246672011263 has 2 divisors, whose sum is σ = 49246672011264. Its totient is φ = 49246672011262.
The previous prime is 49246672011167. The next prime is 49246672011301. The reversal of 49246672011263 is 36211027664294.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 49246672011263 - 226 = 49246604902399 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (49246678011263) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24623336005631 + 24623336005632.
It is an arithmetic number, because the mean of its divisors is an integer number (24623336005632).
Almost surely, 249246672011263 is an apocalyptic number.
49246672011263 is a deficient number, since it is larger than the sum of its proper divisors (1).
49246672011263 is an equidigital number, since it uses as much as digits as its factorization.
49246672011263 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5225472, while the sum is 53.
The spelling of 49246672011263 in words is "forty-nine trillion, two hundred forty-six billion, six hundred seventy-two million, eleven thousand, two hundred sixty-three".
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