Base | Representation |
---|---|
bin | 11101011001001… |
… | …010001011110101 |
3 | 1021100220211110202 |
4 | 131121022023311 |
5 | 2002220301311 |
6 | 120533330245 |
7 | 15135401102 |
oct | 3531121365 |
9 | 1240824422 |
10 | 493134581 |
11 | 2333a8345 |
12 | 119196985 |
13 | 7b220214 |
14 | 496c9aa9 |
15 | 2d45de3b |
hex | 1d64a2f5 |
493134581 has 2 divisors, whose sum is σ = 493134582. Its totient is φ = 493134580.
The previous prime is 493134541. The next prime is 493134583. The reversal of 493134581 is 185431394.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 385493956 + 107640625 = 19634^2 + 10375^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-493134581 is a prime.
It is a super-2 number, since 2×4931345812 = 486363429956091122, which contains 22 as substring.
Together with 493134583, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (493134583) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 246567290 + 246567291.
It is an arithmetic number, because the mean of its divisors is an integer number (246567291).
Almost surely, 2493134581 is an apocalyptic number.
It is an amenable number.
493134581 is a deficient number, since it is larger than the sum of its proper divisors (1).
493134581 is an equidigital number, since it uses as much as digits as its factorization.
493134581 is an evil number, because the sum of its binary digits is even.
The product of its digits is 51840, while the sum is 38.
The square root of 493134581 is about 22206.6337160768. The cubic root of 493134581 is about 790.0510467469.
The spelling of 493134581 in words is "four hundred ninety-three million, one hundred thirty-four thousand, five hundred eighty-one".
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