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4933117 = 7704731
BaseRepresentation
bin10010110100010111111101
3100021121222001
4102310113331
52230324432
6253422301
756634160
oct22642775
910247861
104933117
11286a362
12179a991
131039507
14925ad7
156769e7
hex4b45fd

4933117 has 4 divisors (see below), whose sum is σ = 5637856. Its totient is φ = 4228380.

The previous prime is 4933087. The next prime is 4933127. The reversal of 4933117 is 7113394.

4933117 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4933117 is a prime.

It is an Ulam number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4933127) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 352359 + ... + 352372.

It is an arithmetic number, because the mean of its divisors is an integer number (1409464).

Almost surely, 24933117 is an apocalyptic number.

It is an amenable number.

4933117 is a deficient number, since it is larger than the sum of its proper divisors (704739).

4933117 is an equidigital number, since it uses as much as digits as its factorization.

4933117 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 704738.

The product of its digits is 2268, while the sum is 28.

The square root of 4933117 is about 2221.0621333047. The cubic root of 4933117 is about 170.2317140133.

It can be divided in two parts, 4933 and 117, that added together give a triangular number (5050 = T100).

The spelling of 4933117 in words is "four million, nine hundred thirty-three thousand, one hundred seventeen".

Divisors: 1 7 704731 4933117