Base | Representation |
---|---|
bin | 1110010111100010000… |
… | …01010010111011111101 |
3 | 1202012020201001100121222 |
4 | 13023301001102323331 |
5 | 31042013444424014 |
6 | 1014442215403125 |
7 | 50444413042163 |
oct | 7136101227375 |
9 | 1665221040558 |
10 | 493669920509 |
11 | 180400889047 |
12 | 7b8150834a5 |
13 | 37725881ccc |
14 | 19c72651233 |
15 | cc9504908e |
hex | 72f1052efd |
493669920509 has 2 divisors, whose sum is σ = 493669920510. Its totient is φ = 493669920508.
The previous prime is 493669920407. The next prime is 493669920511. The reversal of 493669920509 is 905029966394.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 257744059225 + 235925861284 = 507685^2 + 485722^2 .
It is a cyclic number.
It is not a de Polignac number, because 493669920509 - 28 = 493669920253 is a prime.
Together with 493669920511, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (493669920599) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 246834960254 + 246834960255.
It is an arithmetic number, because the mean of its divisors is an integer number (246834960255).
Almost surely, 2493669920509 is an apocalyptic number.
It is an amenable number.
493669920509 is a deficient number, since it is larger than the sum of its proper divisors (1).
493669920509 is an equidigital number, since it uses as much as digits as its factorization.
493669920509 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28343520, while the sum is 62.
The spelling of 493669920509 in words is "four hundred ninety-three billion, six hundred sixty-nine million, nine hundred twenty thousand, five hundred nine".
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