Base | Representation |
---|---|
bin | 100011111101110100111… |
… | …0000111100101110110011 |
3 | 122111120002112021221100021 |
4 | 1013323221300330232303 |
5 | 1121442014341012040 |
6 | 14302502231304311 |
7 | 1020062322254305 |
oct | 107735160745663 |
9 | 18446075257307 |
10 | 4943134313395 |
11 | 163640a4a8553 |
12 | 67a01981b097 |
13 | 29b19bab74b5 |
14 | 13136b29d975 |
15 | 888b024424a |
hex | 47ee9c3cbb3 |
4943134313395 has 8 divisors (see below), whose sum is σ = 5990491485360. Its totient is φ = 3915353911200.
The previous prime is 4943134313363. The next prime is 4943134313399. The reversal of 4943134313395 is 5933134313494.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 4943134313395 - 25 = 4943134313363 is a prime.
It is not an unprimeable number, because it can be changed into a prime (4943134313399) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4894191885 + ... + 4894192894.
It is an arithmetic number, because the mean of its divisors is an integer number (748811435670).
Almost surely, 24943134313395 is an apocalyptic number.
4943134313395 is a deficient number, since it is larger than the sum of its proper divisors (1047357171965).
4943134313395 is a wasteful number, since it uses less digits than its factorization.
4943134313395 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9788384885.
The product of its digits is 6298560, while the sum is 52.
Subtracting 4943134313395 from its reverse (5933134313494), we obtain a palindrome (990000000099).
The spelling of 4943134313395 in words is "four trillion, nine hundred forty-three billion, one hundred thirty-four million, three hundred thirteen thousand, three hundred ninety-five".
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