Base | Representation |
---|---|
bin | 101110000110111100… |
… | …010111111111001011 |
3 | 11201210100012011212202 |
4 | 232012330113333023 |
5 | 1302343201122331 |
6 | 34424405230415 |
7 | 3401604163526 |
oct | 560674277713 |
9 | 151710164782 |
10 | 49508614091 |
11 | 19aa635a5a2 |
12 | 971840240b |
13 | 4890012731 |
14 | 257937bbbd |
15 | 144b67decb |
hex | b86f17fcb |
49508614091 has 2 divisors, whose sum is σ = 49508614092. Its totient is φ = 49508614090.
The previous prime is 49508614073. The next prime is 49508614109. The reversal of 49508614091 is 19041680594.
Together with next prime (49508614109) it forms an Ormiston pair, because they use the same digits, order apart.
It is a balanced prime because it is at equal distance from previous prime (49508614073) and next prime (49508614109).
It is a cyclic number.
It is not a de Polignac number, because 49508614091 - 26 = 49508614027 is a prime.
It is a super-3 number, since 3×495086140913 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (49508614061) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24754307045 + 24754307046.
It is an arithmetic number, because the mean of its divisors is an integer number (24754307046).
Almost surely, 249508614091 is an apocalyptic number.
49508614091 is a deficient number, since it is larger than the sum of its proper divisors (1).
49508614091 is an equidigital number, since it uses as much as digits as its factorization.
49508614091 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 311040, while the sum is 47.
The spelling of 49508614091 in words is "forty-nine billion, five hundred eight million, six hundred fourteen thousand, ninety-one".
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