Base | Representation |
---|---|
bin | 100100000010011100110… |
… | …1110100010010110110111 |
3 | 122112111201200010101002102 |
4 | 1020010321232202112313 |
5 | 1122122334320333301 |
6 | 14311223525332315 |
7 | 1020563405404223 |
oct | 110047156422667 |
9 | 18474650111072 |
10 | 4953065792951 |
11 | 163a6465720a1 |
12 | 67bb2b86709b |
13 | 29c0c2533713 |
14 | 131a302a7783 |
15 | 88c920b9b6b |
hex | 48139ba25b7 |
4953065792951 has 2 divisors, whose sum is σ = 4953065792952. Its totient is φ = 4953065792950.
The previous prime is 4953065792867. The next prime is 4953065792953. The reversal of 4953065792951 is 1592975603594.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4953065792951 is a prime.
Together with 4953065792953, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4953065792953) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2476532896475 + 2476532896476.
It is an arithmetic number, because the mean of its divisors is an integer number (2476532896476).
Almost surely, 24953065792951 is an apocalyptic number.
4953065792951 is a deficient number, since it is larger than the sum of its proper divisors (1).
4953065792951 is an equidigital number, since it uses as much as digits as its factorization.
4953065792951 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 91854000, while the sum is 65.
The spelling of 4953065792951 in words is "four trillion, nine hundred fifty-three billion, sixty-five million, seven hundred ninety-two thousand, nine hundred fifty-one".
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