Base | Representation |
---|---|
bin | 1110011010100101110… |
… | …10110001111100000010 |
3 | 1202100111011121221000000 |
4 | 13031102322301330002 |
5 | 31103344432122100 |
6 | 1015313211140430 |
7 | 50533205521614 |
oct | 7152272617402 |
9 | 1670434557000 |
10 | 495312379650 |
11 | 181073a1a9a0 |
12 | 7bbb3144716 |
13 | 37927c32a1a |
14 | 19d8a838db4 |
15 | cd3e333900 |
hex | 7352eb1f02 |
495312379650 has 336 divisors, whose sum is σ = 1541958406560. Its totient is φ = 117279187200.
The previous prime is 495312379649. The next prime is 495312379663. The reversal of 495312379650 is 56973213594.
495312379650 is a `hidden beast` number, since 49 + 531 + 2 + 3 + 7 + 9 + 65 + 0 = 666.
It is a Harshad number since it is a multiple of its sum of digits (54).
It is a Curzon number.
It is an unprimeable number.
It is a polite number, since it can be written in 167 ways as a sum of consecutive naturals, for example, 17226486 + ... + 17255214.
Almost surely, 2495312379650 is an apocalyptic number.
It is a practical number, because each smaller number is the sum of distinct divisors of 495312379650, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (770979203280).
495312379650 is an abundant number, since it is smaller than the sum of its proper divisors (1046646026910).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
495312379650 is a wasteful number, since it uses less digits than its factorization.
495312379650 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28813 (or 28793 counting only the distinct ones).
The product of its (nonzero) digits is 6123600, while the sum is 54.
The spelling of 495312379650 in words is "four hundred ninety-five billion, three hundred twelve million, three hundred seventy-nine thousand, six hundred fifty".
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