Base | Representation |
---|---|
bin | 101110001000100010… |
… | …010101000101110101 |
3 | 11201212012111001012012 |
4 | 232020202111011311 |
5 | 1302422021402132 |
6 | 34431202134005 |
7 | 3402350310356 |
oct | 561042250565 |
9 | 151765431165 |
10 | 49535340917 |
11 | 1a00a454887 |
12 | 9725351305 |
13 | 489570c91a |
14 | 257cb37d2d |
15 | 144dbad0b2 |
hex | b88895175 |
49535340917 has 2 divisors, whose sum is σ = 49535340918. Its totient is φ = 49535340916.
The previous prime is 49535340893. The next prime is 49535340919. The reversal of 49535340917 is 71904353594.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 49530282916 + 5058001 = 222554^2 + 2249^2 .
It is a cyclic number.
It is not a de Polignac number, because 49535340917 - 216 = 49535275381 is a prime.
Together with 49535340919, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (49535340919) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24767670458 + 24767670459.
It is an arithmetic number, because the mean of its divisors is an integer number (24767670459).
Almost surely, 249535340917 is an apocalyptic number.
It is an amenable number.
49535340917 is a deficient number, since it is larger than the sum of its proper divisors (1).
49535340917 is an equidigital number, since it uses as much as digits as its factorization.
49535340917 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2041200, while the sum is 50.
The spelling of 49535340917 in words is "forty-nine billion, five hundred thirty-five million, three hundred forty thousand, nine hundred seventeen".
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