Base | Representation |
---|---|
bin | 100100000011011001011… |
… | …1110011010111100110011 |
3 | 122112200222102211210122010 |
4 | 1020012302332122330303 |
5 | 1122141021100000201 |
6 | 14312201433414003 |
7 | 1020664666026165 |
oct | 110066276327463 |
9 | 18480872753563 |
10 | 4955100000051 |
11 | 164049a852a93 |
12 | 6803b8b6a303 |
13 | 29c357ac6966 |
14 | 131b84508935 |
15 | 88d60987bd6 |
hex | 481b2f9af33 |
4955100000051 has 16 divisors (see below), whose sum is σ = 7080377912064. Its totient is φ = 3074374616544.
The previous prime is 4955100000041. The next prime is 4955100000077. The reversal of 4955100000051 is 1500000015594.
It is not a de Polignac number, because 4955100000051 - 26 = 4955099999987 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4955099999964 and 4955100000018.
It is not an unprimeable number, because it can be changed into a prime (4955100000031) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 970443981 + ... + 970449086.
It is an arithmetic number, because the mean of its divisors is an integer number (442523619504).
Almost surely, 24955100000051 is an apocalyptic number.
4955100000051 is a deficient number, since it is larger than the sum of its proper divisors (2125277912013).
4955100000051 is a wasteful number, since it uses less digits than its factorization.
4955100000051 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1940893130.
The product of its (nonzero) digits is 4500, while the sum is 30.
The spelling of 4955100000051 in words is "four trillion, nine hundred fifty-five billion, one hundred million, fifty-one", and thus it is an aban number.
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