Base | Representation |
---|---|
bin | 100100000101000010101… |
… | …1101010101011101011111 |
3 | 122120001002112122102002022 |
4 | 1020022011131111131133 |
5 | 1122220234104210031 |
6 | 14313544102050355 |
7 | 1021151335530641 |
oct | 110120535253537 |
9 | 18501075572068 |
10 | 4958631319391 |
11 | 1641a42121522 |
12 | 6810237199bb |
13 | 29c79b5aa929 |
14 | 131ddb4da891 |
15 | 88eba9ce97b |
hex | 4828575575f |
4958631319391 has 2 divisors, whose sum is σ = 4958631319392. Its totient is φ = 4958631319390.
The previous prime is 4958631319381. The next prime is 4958631319393. The reversal of 4958631319391 is 1939131368594.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4958631319391 - 210 = 4958631318367 is a prime.
It is a super-2 number, since 2×49586313193912 (a number of 26 digits) contains 22 as substring.
Together with 4958631319393, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4958631319393) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2479315659695 + 2479315659696.
It is an arithmetic number, because the mean of its divisors is an integer number (2479315659696).
Almost surely, 24958631319391 is an apocalyptic number.
4958631319391 is a deficient number, since it is larger than the sum of its proper divisors (1).
4958631319391 is an equidigital number, since it uses as much as digits as its factorization.
4958631319391 is an evil number, because the sum of its binary digits is even.
The product of its digits is 18895680, while the sum is 62.
The spelling of 4958631319391 in words is "four trillion, nine hundred fifty-eight billion, six hundred thirty-one million, three hundred nineteen thousand, three hundred ninety-one".
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