Base | Representation |
---|---|
bin | 11101100100100… |
… | …001100011101101 |
3 | 1021120112012022221 |
4 | 131210201203231 |
5 | 2004001121101 |
6 | 121121235341 |
7 | 15202620133 |
oct | 3544414355 |
9 | 1246465287 |
10 | 496113901 |
11 | 235052798 |
12 | 11a192b51 |
13 | 7ba2432a |
14 | 49c63753 |
15 | 2d84baa1 |
hex | 1d9218ed |
496113901 has 2 divisors, whose sum is σ = 496113902. Its totient is φ = 496113900.
The previous prime is 496113889. The next prime is 496113929. The reversal of 496113901 is 109311694.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 408242025 + 87871876 = 20205^2 + 9374^2 .
It is a cyclic number.
It is not a de Polignac number, because 496113901 - 25 = 496113869 is a prime.
It is a super-2 number, since 2×4961139012 = 492258005530875602, which contains 22 as substring.
It is equal to p26161972 and since 496113901 and 26161972 have the same sum of digits, it is a Honaker prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (496113001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 248056950 + 248056951.
It is an arithmetic number, because the mean of its divisors is an integer number (248056951).
Almost surely, 2496113901 is an apocalyptic number.
It is an amenable number.
496113901 is a deficient number, since it is larger than the sum of its proper divisors (1).
496113901 is an equidigital number, since it uses as much as digits as its factorization.
496113901 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5832, while the sum is 34.
The square root of 496113901 is about 22273.6144574696. The cubic root of 496113901 is about 791.6389097464.
The spelling of 496113901 in words is "four hundred ninety-six million, one hundred thirteen thousand, nine hundred one".
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