Base | Representation |
---|---|
bin | 101110001101111011… |
… | …000001111111101101 |
3 | 11202002111111212211002 |
4 | 232031323001333231 |
5 | 1303113134434011 |
6 | 34444151010045 |
7 | 3404525340023 |
oct | 561573017755 |
9 | 152074455732 |
10 | 49625702381 |
11 | 1a056462782 |
12 | 974b669925 |
13 | 48ab35a248 |
14 | 258ab3a713 |
15 | 1456aabc3b |
hex | b8dec1fed |
49625702381 has 2 divisors, whose sum is σ = 49625702382. Its totient is φ = 49625702380.
The previous prime is 49625702353. The next prime is 49625702447. The reversal of 49625702381 is 18320752694.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 49528502500 + 97199881 = 222550^2 + 9859^2 .
It is a cyclic number.
It is not a de Polignac number, because 49625702381 - 234 = 32445833197 is a prime.
It is a super-2 number, since 2×496257023812 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (49625701381) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24812851190 + 24812851191.
It is an arithmetic number, because the mean of its divisors is an integer number (24812851191).
It is a 1-persistent number, because it is pandigital, but 2⋅49625702381 = 99251404762 is not.
Almost surely, 249625702381 is an apocalyptic number.
It is an amenable number.
49625702381 is a deficient number, since it is larger than the sum of its proper divisors (1).
49625702381 is an equidigital number, since it uses as much as digits as its factorization.
49625702381 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 725760, while the sum is 47.
The spelling of 49625702381 in words is "forty-nine billion, six hundred twenty-five million, seven hundred two thousand, three hundred eighty-one".
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