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49690091153 is a prime number
BaseRepresentation
bin101110010001110000…
…101001111010010001
311202020222200011121102
4232101300221322101
51303231130404103
634454411034145
73406236543263
oct562160517221
9152228604542
1049690091153
111a089840a3a
12976913b955
1348bb7b2a01
1425954dbb33
15145c579e88
hexb91c29e91

49690091153 has 2 divisors, whose sum is σ = 49690091154. Its totient is φ = 49690091152.

The previous prime is 49690091149. The next prime is 49690091167. The reversal of 49690091153 is 35119009694.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 25131126784 + 24558964369 = 158528^2 + 156713^2 .

It is a cyclic number.

It is not a de Polignac number, because 49690091153 - 22 = 49690091149 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 49690091098 and 49690091107.

It is not a weakly prime, because it can be changed into another prime (49690021153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24845045576 + 24845045577.

It is an arithmetic number, because the mean of its divisors is an integer number (24845045577).

Almost surely, 249690091153 is an apocalyptic number.

It is an amenable number.

49690091153 is a deficient number, since it is larger than the sum of its proper divisors (1).

49690091153 is an equidigital number, since it uses as much as digits as its factorization.

49690091153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 262440, while the sum is 47.

The spelling of 49690091153 in words is "forty-nine billion, six hundred ninety million, ninety-one thousand, one hundred fifty-three".