Base | Representation |
---|---|
bin | 1110011110000000110… |
… | …01001000111111110101 |
3 | 1202112020011122200212200 |
4 | 13033000121020333311 |
5 | 31121130124224330 |
6 | 1020215341335113 |
7 | 50626550146263 |
oct | 7170031107765 |
9 | 1675204580780 |
10 | 497149054965 |
11 | 181926754282 |
12 | 80426267499 |
13 | 37b5b5c4254 |
14 | 1a0c273b433 |
15 | cdea6d3a60 |
hex | 73c0648ff5 |
497149054965 has 48 divisors (see below), whose sum is σ = 931594684800. Its totient is φ = 244402137216.
The previous prime is 497149054939. The next prime is 497149054981. The reversal of 497149054965 is 569450941794.
497149054965 is a `hidden beast` number, since 4 + 9 + 7 + 1 + 490 + 54 + 96 + 5 = 666.
It is not a de Polignac number, because 497149054965 - 27 = 497149054837 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 7825945 + ... + 7889214.
It is an arithmetic number, because the mean of its divisors is an integer number (19408222600).
Almost surely, 2497149054965 is an apocalyptic number.
497149054965 is a gapful number since it is divisible by the number (45) formed by its first and last digit.
It is an amenable number.
497149054965 is a deficient number, since it is larger than the sum of its proper divisors (434445629835).
497149054965 is a wasteful number, since it uses less digits than its factorization.
497149054965 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15715226 (or 15715223 counting only the distinct ones).
The product of its (nonzero) digits is 48988800, while the sum is 63.
The spelling of 497149054965 in words is "four hundred ninety-seven billion, one hundred forty-nine million, fifty-four thousand, nine hundred sixty-five".
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