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49752145 = 59950429
BaseRepresentation
bin1011110111001…
…0100001010001
310110121200010001
42331302201101
5100214032040
64534210001
71142612662
oct275624121
9113550101
1049752145
11260a1583
12147b3901
13a3cc651
146871369
15457b59a
hex2f72851

49752145 has 4 divisors (see below), whose sum is σ = 59702580. Its totient is φ = 39801712.

The previous prime is 49752137. The next prime is 49752169. The reversal of 49752145 is 54125794.

49752145 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 19820304 + 29931841 = 4452^2 + 5471^2 .

It is a cyclic number.

It is not a de Polignac number, because 49752145 - 23 = 49752137 is a prime.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4975210 + ... + 4975219.

It is an arithmetic number, because the mean of its divisors is an integer number (14925645).

Almost surely, 249752145 is an apocalyptic number.

It is an amenable number.

49752145 is a deficient number, since it is larger than the sum of its proper divisors (9950435).

49752145 is an equidigital number, since it uses as much as digits as its factorization.

49752145 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9950434.

The product of its digits is 50400, while the sum is 37.

The square root of 49752145 is about 7053.5200432125. The cubic root of 49752145 is about 367.7934041432.

The spelling of 49752145 in words is "forty-nine million, seven hundred fifty-two thousand, one hundred forty-five".

Divisors: 1 5 9950429 49752145