Base | Representation |
---|---|
bin | 101110010111111001… |
… | …110000000100111000 |
3 | 11202112011120112200100 |
4 | 232113321300010320 |
5 | 1303434020422000 |
6 | 34512531435400 |
7 | 3411630461313 |
oct | 562771600470 |
9 | 152464515610 |
10 | 49793139000 |
11 | 1a131a24350 |
12 | 9797755b60 |
13 | 4906c52877 |
14 | 25a508397a |
15 | 1466632a00 |
hex | b97e70138 |
49793139000 has 192 divisors, whose sum is σ = 183601248480. Its totient is φ = 12071040000.
The previous prime is 49793138977. The next prime is 49793139041. The reversal of 49793139000 is 93139794.
49793139000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-3 number, since 3×497931390003 (a number of 33 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (45).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 152481 + ... + 350480.
Almost surely, 249793139000 is an apocalyptic number.
49793139000 is a gapful number since it is divisible by the number (40) formed by its first and last digit.
It is an amenable number.
49793139000 is an abundant number, since it is smaller than the sum of its proper divisors (133808109480).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
49793139000 is a wasteful number, since it uses less digits than its factorization.
49793139000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 502999 (or 502982 counting only the distinct ones).
The product of its (nonzero) digits is 183708, while the sum is 45.
The spelling of 49793139000 in words is "forty-nine billion, seven hundred ninety-three million, one hundred thirty-nine thousand".
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