Base | Representation |
---|---|
bin | 1110100010110100100… |
… | …10101110011011011111 |
3 | 1202202220010011101011001 |
4 | 13101122102232123133 |
5 | 31141422123031133 |
6 | 1021323455011131 |
7 | 51050541651064 |
oct | 7213222563337 |
9 | 1682803141131 |
10 | 499731064543 |
11 | 182a31181297 |
12 | 80a26b09aa7 |
13 | 38180508679 |
14 | 1a289618c6b |
15 | ceec20d87d |
hex | 745a4ae6df |
499731064543 has 2 divisors, whose sum is σ = 499731064544. Its totient is φ = 499731064542.
The previous prime is 499731064523. The next prime is 499731064549. The reversal of 499731064543 is 345460137994.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 499731064543 - 221 = 499728967391 is a prime.
It is a super-3 number, since 3×4997310645433 (a number of 36 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (499731064549) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 249865532271 + 249865532272.
It is an arithmetic number, because the mean of its divisors is an integer number (249865532272).
Almost surely, 2499731064543 is an apocalyptic number.
499731064543 is a deficient number, since it is larger than the sum of its proper divisors (1).
499731064543 is an equidigital number, since it uses as much as digits as its factorization.
499731064543 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9797760, while the sum is 55.
The spelling of 499731064543 in words is "four hundred ninety-nine billion, seven hundred thirty-one million, sixty-four thousand, five hundred forty-three".
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