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499731064543 is a prime number
BaseRepresentation
bin1110100010110100100…
…10101110011011011111
31202202220010011101011001
413101122102232123133
531141422123031133
61021323455011131
751050541651064
oct7213222563337
91682803141131
10499731064543
11182a31181297
1280a26b09aa7
1338180508679
141a289618c6b
15ceec20d87d
hex745a4ae6df

499731064543 has 2 divisors, whose sum is σ = 499731064544. Its totient is φ = 499731064542.

The previous prime is 499731064523. The next prime is 499731064549. The reversal of 499731064543 is 345460137994.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 499731064543 - 221 = 499728967391 is a prime.

It is a super-3 number, since 3×4997310645433 (a number of 36 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (499731064549) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 249865532271 + 249865532272.

It is an arithmetic number, because the mean of its divisors is an integer number (249865532272).

Almost surely, 2499731064543 is an apocalyptic number.

499731064543 is a deficient number, since it is larger than the sum of its proper divisors (1).

499731064543 is an equidigital number, since it uses as much as digits as its factorization.

499731064543 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9797760, while the sum is 55.

The spelling of 499731064543 in words is "four hundred ninety-nine billion, seven hundred thirty-one million, sixty-four thousand, five hundred forty-three".