Base | Representation |
---|---|
bin | 1110100011010100101… |
… | …00100000101110000011 |
3 | 1202210120212011002112012 |
4 | 13101222110200232003 |
5 | 31142444442440011 |
6 | 1021410302323135 |
7 | 51060315414416 |
oct | 7215224405603 |
9 | 1683525132465 |
10 | 499999968131 |
11 | 183059a46564 |
12 | 80aa0b894ab |
13 | 381c4139411 |
14 | 1a2b3215b7d |
15 | d015b28a8b |
hex | 746a520b83 |
499999968131 has 2 divisors, whose sum is σ = 499999968132. Its totient is φ = 499999968130.
The previous prime is 499999968113. The next prime is 499999968133. The reversal of 499999968131 is 131869999994.
Together with previous prime (499999968113) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 499999968131 - 214 = 499999951747 is a prime.
It is a super-2 number, since 2×4999999681312 (a number of 24 digits) contains 22 as substring.
Together with 499999968133, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (499999968133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 249999984065 + 249999984066.
It is an arithmetic number, because the mean of its divisors is an integer number (249999984066).
Almost surely, 2499999968131 is an apocalyptic number.
499999968131 is a deficient number, since it is larger than the sum of its proper divisors (1).
499999968131 is an equidigital number, since it uses as much as digits as its factorization.
499999968131 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 306110016, while the sum is 77.
The spelling of 499999968131 in words is "four hundred ninety-nine billion, nine hundred ninety-nine million, nine hundred sixty-eight thousand, one hundred thirty-one".
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