Base | Representation |
---|---|
bin | 100100011000010011100… |
… | …1110010100110101000111 |
3 | 122200222212121010002110101 |
4 | 1020300213032110311013 |
5 | 1123404444444434203 |
6 | 14344545052304531 |
7 | 1024144442520121 |
oct | 110604716246507 |
9 | 18628777102411 |
10 | 4999999999303 |
11 | 1658540716a91 |
12 | 689049a72147 |
13 | 2a3662093b5a |
14 | 134003786211 |
15 | 8a0dc72141d |
hex | 48c27394d47 |
4999999999303 has 2 divisors, whose sum is σ = 4999999999304. Its totient is φ = 4999999999302.
The previous prime is 4999999999273. The next prime is 4999999999307. The reversal of 4999999999303 is 3039999999994.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4999999999303 - 217 = 4999999868231 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4999999999199 and 4999999999208.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4999999999307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2499999999651 + 2499999999652.
It is an arithmetic number, because the mean of its divisors is an integer number (2499999999652).
Almost surely, 24999999999303 is an apocalyptic number.
4999999999303 is a deficient number, since it is larger than the sum of its proper divisors (1).
4999999999303 is an equidigital number, since it uses as much as digits as its factorization.
4999999999303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13947137604, while the sum is 91.
The spelling of 4999999999303 in words is "four trillion, nine hundred ninety-nine billion, nine hundred ninety-nine million, nine hundred ninety-nine thousand, three hundred three".
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