Base | Representation |
---|---|
bin | 100100011000010011100… |
… | …1110010101000000110101 |
3 | 122200222212121010010111011 |
4 | 1020300213032111000311 |
5 | 1123410000000000203 |
6 | 14344545052312221 |
7 | 1024144442522242 |
oct | 110604716250065 |
9 | 18628777103434 |
10 | 5000000000053 |
11 | 1658540717603 |
12 | 689049a72671 |
13 | 2a36620942b6 |
14 | 1340037865c9 |
15 | 8a0dc72176d |
hex | 48c27395035 |
5000000000053 has 2 divisors, whose sum is σ = 5000000000054. Its totient is φ = 5000000000052.
The previous prime is 4999999999937. The next prime is 5000000000101. The reversal of 5000000000053 is 3500000000005.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4997938658449 + 2061341604 = 2235607^2 + 45402^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5000000000053 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4999999999952 and 5000000000042.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5000000000353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2500000000026 + 2500000000027.
It is an arithmetic number, because the mean of its divisors is an integer number (2500000000027).
Almost surely, 25000000000053 is an apocalyptic number.
It is an amenable number.
5000000000053 is a deficient number, since it is larger than the sum of its proper divisors (1).
5000000000053 is an equidigital number, since it uses as much as digits as its factorization.
5000000000053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 75, while the sum is 13.
Adding to 5000000000053 its reverse (3500000000005), we get a palindrome (8500000000058).
The spelling of 5000000000053 in words is "five trillion, fifty-three", and thus it is an aban number and an uban number.
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