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50000499551 = 101495054451
BaseRepresentation
bin101110100100010000…
…110001001101011111
311210001121202112212202
4232210100301031133
51304400111441201
634545300122115
73420026143112
oct564420611537
9153047675782
1050000499551
111a228a84402
12983509633b
13493abb6212
1425c4820579
151479942c6b
hexba443135f

50000499551 has 4 divisors (see below), whose sum is σ = 50495554104. Its totient is φ = 49505445000.

The previous prime is 50000499533. The next prime is 50000499557. The reversal of 50000499551 is 15599400005.

50000499551 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 50000499551 - 214 = 50000483167 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (50000499557) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 247527125 + ... + 247527326.

It is an arithmetic number, because the mean of its divisors is an integer number (12623888526).

Almost surely, 250000499551 is an apocalyptic number.

50000499551 is a deficient number, since it is larger than the sum of its proper divisors (495054553).

50000499551 is a wasteful number, since it uses less digits than its factorization.

50000499551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 495054552.

The product of its (nonzero) digits is 40500, while the sum is 38.

Adding to 50000499551 its reverse (15599400005), we get a palindrome (65599899556).

The spelling of 50000499551 in words is "fifty billion, four hundred ninety-nine thousand, five hundred fifty-one".

Divisors: 1 101 495054451 50000499551