Base | Representation |
---|---|
bin | 10110101111001101010010… |
… | …00001011000100010100111 |
3 | 20120001000011022002102000211 |
4 | 23113212221001120202213 |
5 | 23023202111300124103 |
6 | 254201534025520251 |
7 | 13350264145403011 |
oct | 1327465101304247 |
9 | 216030138072024 |
10 | 50000550004903 |
11 | 14a28128a699a3 |
12 | 5736537043087 |
13 | 21b9054665774 |
14 | c4c07a6991b1 |
15 | 5ba9680a436d |
hex | 2d79a90588a7 |
50000550004903 has 2 divisors, whose sum is σ = 50000550004904. Its totient is φ = 50000550004902.
The previous prime is 50000550004901. The next prime is 50000550004927. The reversal of 50000550004903 is 30940005500005.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 50000550004903 - 21 = 50000550004901 is a prime.
Together with 50000550004901, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50000550004901) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25000275002451 + 25000275002452.
It is an arithmetic number, because the mean of its divisors is an integer number (25000275002452).
Almost surely, 250000550004903 is an apocalyptic number.
50000550004903 is a deficient number, since it is larger than the sum of its proper divisors (1).
50000550004903 is an equidigital number, since it uses as much as digits as its factorization.
50000550004903 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13500, while the sum is 31.
Adding to 50000550004903 its reverse (30940005500005), we get a palindrome (80940555504908).
The spelling of 50000550004903 in words is "fifty trillion, five hundred fifty million, four thousand, nine hundred three".
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